Two 0.55-kg basketballs, each with a radius of 19 cm , are just touching. You may want to review (Pages 399 - 401) . Part A How much energy is required to change the separation between the centers of the basketballs to 1.4 m ? (Ignore any other gravitational interactions.)

      ΔU = - 9,179 10-11 J

Explanation:

For this exercise the two basketballs are linked by gravitational interaction, so we can use gravitational energy

               U = - G m₁m₂ / R

In this case the mass is equal and the initial distance is r₁ = 19 cm = 0.19 m

               U₁ = - G m² / r₁

let's calculate

              U₁ = - 6.67 10⁻¹¹ 0.55² / 0.19

              U₁ = - 10,619 10⁻¹¹ J

when its centers are separated it is at r₂ = 1.4 m

              U₂ = - 6.67 10⁻¹¹ 0.55² / 1.4

              U₂ = - 1.44 10-11 J

the energy between these two points is

          ΔU = U₂ - U₁

          ΔU = (-1.44 +10.619) 10-11

          ΔU = - 9,179 10-11 J

as we know our atmosphere or air have different levels. every level has other gasses, and every gas has another permeability. when the light comes from lower permeability to higher permeability, it changes its direction. so that means that when the light comes from the moon to the earth, it changes it's direction many more times. it basically means that the shape of the light part of the moon is changed on the earth.

hope this ! this is not copied! search it up, it's free of plagiarism!

false.

explanation:

this statement is false. after falling for 5 seconds, its speed will not be 100 m/s.