Physics, 09.07.2020 02:01 liamgreene90

A crate is pushed 1.50m horizontally with a force of 2.40N under an opposing force of friction of 0.600N. What is the NET work done on the crate?

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Answer from: Bashirar19

2.7 J

Explanation:

From the question,

The Net work done by the crate = Work done by the crate in moving if through a distance- work done against friction.

W = Fd-F'd Equation 1

Where F = force applied to the crate, d = distance moved by the crate, F' = force of friction

Given: F = 2.4 N, F' = 0.6 N, d = 1.5 m

Substitute these values into equation 1

W = 2.4(1.5)-0.6(1.5)

W = 3.6-0.9

W = 2.7 J

Answer from: Quest

force is based upon mass and acceleration.the statement is not always true.

it can be explained from newton's second law of motion.

as per newton's second law of motion the rate of change of momentum is directly proportional to the applied force and takes place along the direction of force.

mathematically it can be written as -

$f\alpha \frac{dp}{dt}$

⇒ $f= k \frac{dp}{dt}$

here k is the proportionality constant whose value is 1.

$f=\frac{dp}{dt}$

$f= \frac{d[mv]}{dt}$

$f= m\frac{dv}{dt} +v\frac{dm}{dt}$

$f=ma+v\frac{dm}{dt}$ [a is the acceleration=dv/dt]

hence we see that force not only depends on mass and acceleration but also on velocity and rate of change of mass. force f will depend on mass and acceleration only when mass is constant.

hence the statement that force is based upon mass and acceleration is false.

Answer from: Quest

Ithink the answer is c. make unnecessarily wide gestures

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A crate is pushed 1.50m horizontally with a force of 2.40N under an opposing force of friction of 0....