g The radius of a spherical ball increases at a rate of 3 m/s. At what rate is the volume changing when the radius is equal to 2 meters

dV/dt = 150.79 m^3/s

Explanation:

In order to calculate the rate of change of the volume, you calculate the derivative, respect to the radius of the sphere, of the volume of the sphere, as follow:

                    (1)

r: radius of the sphere

You calculate the derivative of the equation (1):

(2)

where dr/dt = 3m/s

You replace the values of dr/dt and r=2m in the equation (2):

The rate of change of the sphere, when it has a radius of 2m, is 150.79m^3/s

okay i have so many questions. but the big one here is: um wt..f is this mess? ?

probably not if net force is zero