The length and diameter of a uniformly charged cylindrical shell are 4.50 m and 0.165 m, respectively. What net charge on the surface of the cylindrical shell will produce an electric field of 4.95 ✕ 104 N/C at a radial distance of 22.0 cm from the axis of the cylinder?

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Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.