Calculate the isochore molar heat capacity of a distiomkc has knowing the molecules mean square velocity of Vr=600m/s at T=27C

Therefore the isochore polar heat capacity of a diatomic is 20. 785 J/mol K

Explanation:

Solution

Recall that:

Vr = 600 m/s

T = 27°C

The molar heat capacity at constant volume is given below:

Cv = R/r -1

Here

r = 1 +2/f

For diatomic f = 5

Thus

r =1 +2/f =7/5

v =R/7/5 - 1

=5R/2 =5/2 * 8.314 J/mol K

Hence Cv = 20. 785 J/mol K

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explanation:

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