Consider the double slit experiment for light. Complete each statement as it would apply to Young's experiment (for each statement select "Increases", "Decreases", or "Cannot be Predicted"). If a variable is not mentioned, consider it to remain unchanged. Required:a. If the distance to the screen decreases, fringe separation:?b. If the frequency of the light used increases, fringe separation:?c. If the wavelength of the light used decreases, fringe separation:?d. For the fringe separation to remain unchanged, wavelength while the distance to the screen decreases. e. If slit separation decreases, fringe separation :?f. If slit separation decreases and the distance to the screen decreases, fringe separation :?g. If the distance to the screen triples and slit separation doubles, fringe separation :?

a)  DECREASE , b) Decreases , c)     DECREASE , d)  the wavelength must increase , e) increasses,

Explanation:

Young's double-slit experience is explained for constructive interference by the expression

          d sin θ = m λ

as in this case, the measured angles are very small,

          tan θ = y / L

         tan θ = sin θ / cos θ = sin θ

          sin θ= y L

        d y / L = m Lam

 we can now examine the statements given

a) if the distance to the screen decreases

        y = m λ / d L

if L decreases and decreases.

The answer is DECREASE

b) if the frequency increases

    the wave speed is

         c = λ f

         λ = c / f

we substitute

          y = (m / d l) c / f

in this case if if the frequency is increased the separation decreases

Decreases

c) If the wavelength decreases

separation decreases

   DECREASE

d) if it is desired that the separation does not change while the separation to the Panamanian decreases the wavelength must increase

      y = (m / d) lam / L

e) if the parcionero between the slits (d) decreases the separation increases

   INCREASES

f) t he gap separation decreases and the distance to the screen decreases so well.

Pattern separation remains constant

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz

1= 26.17

2= 1.17

3=30.86

4=5.86

just took the assigment on edge