Two parallel conducting wires are connected by a light bulb (represented by a resistor). A non ferrous bar is placed across the two wires. The entire setup is placed in a uniform magnetic field. On paper, the wires are drawn horizontally and the magnetic field is out of the page. Initially bar is pulled to the right at a constant speed. Which direction is the current through the circuit formed by the resistor, wires, and bar?a. There no current. b. clockwise c. Counter clockwise.

Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.