The fielder attempts to catch a second ball. Just before the fielder catches the ball, the air resistance acting on the ball is 1.2N. Calculate the resultant force acting on the ball. Remember to include its direction and the unit. Assume the ball is falling vertically

Resultant force = (1.2 - 9.8m)ĵ N

where m = mass of the ball

Magnitude of the resultant force = (9.8m - 1.2) N

Since the weight of the ball is expected to exceed the air resistance (because the ball is falling vertically downwards), the direction of the resultant force is vertically downwards. Its unit is Newtons, the SI unit of Force.

Explanation:

If a ball is falling vertically downwards, the only two forces acting on the ball include the weight of the ball (the pull of gravity on the ball) and the air resistance on the ball.

Weight of the ball acts downwards and is given as mg. where m = mass of the ball and g is the acceleration due to gravity = 9.8 m/s²

W = mg = (9.8m) N

In vector form, W = (-9.8mĵ) N

The air resistance on the ball = 1.2 N, the air resistance acts in the direction opposite the motion of the ball, and since the ball is moving vertically downwards, the air resistance acts vertically upwards.

In vector form, the air resistance = (1.2ĵ) N

Hence, the resultant force acting on the ball is the vector sum of all the forces acting on the ball.

Resultant force = (-9.8mĵ) + (1.2ĵ)

= (1.2 - 9.8m)ĵ N

Since the weight of the ball is expected to exceed the air resistance (because the ball is falling vertically downwards), the direction of the resultant force is vertically downwards.

Hope this Helps!!!

568.98

explanation:

its math