A book weighing 15 N sits on a desk. What is the force the desk is exerting back on the book?

the book is exerting a force of 15N on the table as we know that every action has an equal but opposite reaction so there must be a force acting on it in the opposite direction the other force normal force or we can say it perpendicular force that is defined as a contact force perpendicular to the contact surface that prevent two objects from passing over one another

Explanation:

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the tires are rotating at 0.434 rpmlinear speed=45 m/sdiameter=0.550 mradius=0.275 mnow v= rωω= v/rω=45/0.275ω=163.6 rad/sω=163.6 rad/s (1rev/2π rad) (60s/1m)ω=1563 rpm