An automobile traveling along a straight road increases its speed from 30.0 m/s to 50.0 m/s in a distance of 180 m. If the acceleration is constant, how much time elapses while the auto moves this distance

4.5sec

Explanation:

From the question above, the following are the parameters that are given

u= 30m/s

v= 50m/s

s= 180m

First of all we have to find the acceleration by using the third equation of motion

V^2= U^2 + 2as

50^2= 30^2 + 2(a)(180)

2500= 900 + 360a

Collect the like terms

2500-900= 360a

1600=360a

Divide both sides by the coefficient of a which is 360

1600/360=360a/360

a= 4.44m/s

The next step is to find the time. To do this we will have to use the first equation of motion

v= u + at

50= 30 + 4.44t

Collect the like terms

50-30= 4.44t

20= 4.44t

Divide both sides by the coefficient of t which is 4.44

20/4.44= 4.44t/4.44

t= 4.5sec

Hence 4.5secs elapses while the auto moves at a distance of 180m

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explanation:

physics means: "the branch of science concerned with the nature and properties of matter and energy. the subject matter of physics, distinguished from that of chemistry and biology, includes mechanics, heat, light and other radiation, sound, electricity, magnetism, and the structure of atoms."

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