In order to merge into highway traffic, a car accelerates along a 100.0 m on ramp from rest to 25.0 m/s. How much time does this take?

Explanation:

Using the equation of motion v² = u²+2as to get the acceleration of the body.

v = final velocity (in m/s)

u = initial velocity (in m/s)

a = acceleration (in m/s²)

s = distance covered by the car (in metres)

Given u = 0m/s(the car accelerates from rest)

v = 25m/s

S = 100.0m

on substituting,

25² = 0²+2(100)a

625 = 200a

a = 625/200

a = 3.125 m/s²

Since Acceleration = change in velocity/time

3.125 = 25-0/time

3.125t = 25

t = 25/3.125

t = 8 seconds

It takes 8 seconds to merge into highway traffic.

do you have a formula possibly

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards