A soccer player kicks a ball with initial velocity of 10m/s at an angle of 30 degrees above the horizontalwhat is the magnitude of the vector

10m/s^2

Explanation:

Given the following :

Initial Velocity(U) = 10m/s

Angle of inclination = 30°

In other to calculate the magnitude of the vector,

We need to resolve into verti AL and horizontal component.

Vertical component of a vector(Uy) = U × Sinθ

Horizontal component(Ux) = U × Cosθ

Uy = 10 × sin30 = 10 × 0.5 = 5m/s

Ux = 10 × Cos30 = 10 × 0.866 = 8.66m/s

Therefore the magnitude equals :

U = √(Uy)^2 + (Ux)^2

U = √5^2 + 8.66^2

U = √25 + 74.9956

U = √99.9956

U = 9.9997799

U = 10m/s^2

low freq = 100 mhz

low wavelength =101.7m

length = 3x10^8/freq

a displacement distance is size of displ