frictional force acting on a 0.5 kg object and a floor is 3 N. What is the coefficient of friction between the object and the floor?

μ  = 0.6

Explanation:

F =  μN

N = mg

F = μmg

3 N =  μ*0.5 kg * 9.8 m/s²

μ = 3/(0.5*9.8) = 0.6

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west