Physics, 15.06.2020 02:57 kaiyah2021

A year 11 pupil with a mass of 55kg swinging back on their chair and falling off it at a speed of 0.6m/s. What is his kinetic energy?

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Answer from: mheiser8768

The Kinetic energy will be "9.9 J".

According to the question,

Mass,

m = 55 kg

Speed,

v = 0.6 m/s

As we know,

→ $Kinetic \ energy (K.E.) = \frac{1}{2} mv^2$

By substituting the above values, we get

→ $= \frac{1}{2}\times 55\times (0.6)^2$

→ $= \frac{1}{2}\times 55\times 0.36$

→ $= 55\times 0.18$

→ $= 9.9 \ J$

Thus the above approach is right.

Learn more about Kinetic energy here:

link

A year 11 pupil with a mass of 55kg swinging back on their chair and falling off it at a speed of 0.

Answer from: naocarolina6

Uk = 9.9 J

Explanation:

To calculate the kinetic energie (Uk), you can make use of this formula:

Uk = 0.5 * m * v²

given m = 55 kg and v = 0.6 m/s

Substituting in the formula gives:

Uk = 0.5 * 55 * (0.6)²

Uk = 0.5 * 55 * 0.36

Uk = 9.9 J

Extra:

Now let's examine the formula in relation to the SI units. If you understand the following, it will give you great insight in how smart Phisics is inter twained by looking at formulas and their standard units. It will save you time in future to convert formulas, if you use the right standard units.

The formula for kinetic energie is:

Uk = 0.5 * m * v²

Standard SI unit for mass m is kg.

Standard SI unit for speed v is m/s.

So v * v = v² and therefore v² must have the standard SI unit of m²/s².

From the formula, you see that the unit of Uk must be kg*m²/s² and since Uk is normally given in J, these both forms must be the same !

The main unit for Uk is the Joule. Now please see the picture, which shows the relation between the J and other SI units. Please understand that you can construct your 'own' formulas based these units. Now here is the time saver:

Because almost always the right units are given in a question, or because sometimes you can look up a constant in a table with an exotic and seemingly complicated unit, but that says a lot about the formula which must have been some how involved!

By this, I hope you now understand the implication of using the right standard SI units and how that can help you figure out what formula is needed.