I’m just looking for the solving steps

47.04N

Explanation:

The force applied by the deranged Rugby player who wish to burn excess energy by venting it on a box around is house is as follows;

First coefficient of kinetic friction,μk

μk= Kinetic Frictional Force/Normal reaction

The normal reaction is a vertical force acting opposite to the weight of the object

Hence Normal reaction=mass of object × acceleration of free fall due to gravity (g).

Let g= 9.8m/s

Normal reaction= 15 ×9.8 =147N

Hence kinetic Frictional force = μk×Normal reaction.

0.3×147=44.1N

Now the force applied by the player overcomes the kinetic Frictional force and the object accelerates moving a distance of 5m.

Now the force the object acquires to move a distance of 5m is given by Newton's second law,F =m×a

Where m is mass of object , a is acceleration of object.

Now by looking at the formula above, we don't know acceleration.

Let's calculate the acceleration .

From Newton law of motion.

V2 = U2 + 2aS

U = 0 { the body starts from rest so initial velocity is zero}

S = 5m{ distance of object}

a = ?{ acceleration of object}

Substituting the known values we have;

1.4^2 =0+ 2× a×5

1.96 = 10a

a = 1.96/10= 0.196m/S2

Hence Force of the object =15×0.196= 2.94N

Hence the force applied by the Rugby player is the force required to overcome the frictional force plus that required to accelerate the object

44.1+2.94= 47.04N

Note: I have converted velocity in cm/s to m/s by dividing by 100

measure their densities same density, same sub