A ball is thrown vertically downward with an initial speed of 12.0 m/s from a height of 10.0 m above the ground. Ignoring air resistance, what is the speed of the ball when it reaches the ground? (A) 18.5 m/s
(B) 14.6 m/s
(C) 14.0 m/s
(D) 12.8 m/s
(E) 12.0 m/s
Can you just take a picture of your work clearly because I have to show work. Thanks.

18.5 m/s

Explanation:

Take down to be positive.

Given:

Δy = 10.0 m

v₀ = 12.0 m/s

a = 9.8 m/s²

Find: v

v² = v₀² + 2aΔy

v² = (12.0 m/s)² + 2 (10 m/s²) (10.0 m)

v = 18.5 m/s

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