In the Life Cycle of Stars diagram, what stage does letter J represent? A.) white dwarf

B.) black dwarf

C.) black hole

D.) neutron star

Which letters in the Life Cycle of Stars diagram represent stars on the main sequence?

A.) F & I

B.) C & G

C.) A & E

D.) B & D

In the Life Cycle of Stars diagram, what stage does letter L represent?

A.) neutron star

B.) black hole

C.) white dwarf

D.) black dwarf

In the Life Cycle of Stars diagram, what stage does letter I represent?

A.) neutron star

B.) black dwarf

C.) black hole

D.) white dwarf

In the Life Cycle of Stars diagram, what does letter D represent?

A.) a high mass star

B.) a white dwarf

C.) a cool star

D.) a low mass star

In the Life Cycle of Stars diagram, what stage does letter C represent?

A.) nuclear fusion

B.) a supernova

C.) a planetary nebula

D.) protostar formation

Which letter in the Life Cycle of Stars diagram represents a star forming region of space?

A.) M

B.) H

C.) J

D.) G

Which letter in the Life Cycle of Stars diagram represents a planetary nebula?
Group of answer choices

A.) G

B.) H

C.) L

D.) M

most voltage drop calculators want the distance between the source and destination. then internally, they double it so both the source and return wires are calculated. but you need to know which distance the calculator uses so you're not half of what you should be or double what you should be.

most circuit breakers will not take a #6 directly, so the electrician will have to splice on a smaller pigtail. you also have to upsize the grounding wire when you upsized the ungrounded (hot) wire (see note in 250.122). this will preclude using most cable assemblies, as a cable with #6 copper will most likely only have a #10 grounding conductor. you need a #6 grounding conductor if the circuit is 20a. a #8 cable is no better, as it will have a #10 grounding conductor too. but most 20a breakers will take a #8 directly.

in your related post, you didn't say what type of load this is. if it is a light or heater, voltage drop won't be a big issue. if this is a motor, the current needs are huge at startup and the voltage drop can pose a problem. if this is a motor, knowing if the motor is under much load during startup will answer the voltage drop effect (a saw is easier to start than a compressor).

d

explanation:

v=uf/(u-f)

= 5.10/(5-10) convex lens has positive focal length

=50/-5

=-10 cm (formed at other side)

resonant frequency

the only real purpose of sputnik 1 was to beat the us into space. we were getting close to launching a useful satellite, explorer 1 - which launched on january 31, 1958. the ussr had to beat that, so they launched sputnik 1 on october 4, 19