A particular planet has a moment of inertia of 8.26 × 10^(36) kg⋅m^2 and a mass of 6.54 × 10^22 kg. Based on these values, what is the planet's radius? Hint: Because planets are the shape of a sphere, the moment of inertia is I = (2/5)mr^2.

1.776933x10^7

Explanation:

Moment of inertia I = 8.26x10^36kgm^2

Mass of planet m = 6.54x10^22kg

Also, Planet is solid sphere so that, Moment of inertia is I = _2_ m

R^2= 0.4 R^2                                                                               5

Where R is radius of planet

Putting into calculation

We get,

I = _2_  m R^2

       5

8.26x10^36 = 0.4x6.54x10^22xR^2

8.26x10^14 = 2.616 R^2

R = 1.776933x10^7

answer would be d.) i hope this

explanation:

that would be b i just took the test : )