The heating element in an electric kettle is rated as 2.0 kW. If the water in the kettle is at 100.0 °C, what volume of water will be converted into steam in one minute? The specific latent heat of vaporization of the water is 2,257,000 J/kg and the 3 density of water is 1,000 kg/m .

The volume is  

Explanation:

From the question we are told that

    The power of the heating element is

    The temperature of the water in the kettle is  

     The time to convert water to steam is t = 1 minute = 60 sec

      The specific latent heat of vaporization is

      The density of water is

The power of the heating element is mathematically represented as

Where E  Energy generated by the heating element in term of heat

substituting values

Now

 The latent heat of vaporization is mathematically represented as

Where m is the mass of water converted to steam

 So

substituting values

The volume of water converted to steam is mathematically evaluated as

substituting values

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west