HELP ME I'M DESPERATE PHYSICS EASY 40 POINTSS 1.A car moving with a speed of 108 km/h is brought to rest in a distance of 60 m. How much time did the car take to stop?
2 seconds
4 seconds
6 seconds
8 seconds

2.A student standing on the ground next to a tall building throws a ball straight up with a speed of 39.2 m/s. If it takes the ball 4 seconds to reach the same height as the top of the building, how tall is the building?
a.44.1 m
b.78.4 m
c.161.7 m
d.235.2 m
3.A boy throws a ball with an initial velocity of 19.6 m/s and it returns to his hands in 4 seconds. What maximum height does the ball reach?
4.9 m
9.8 m
19.6 m
39.4 m

see below

Explanation:

1. 108km/hr

= 108/3.6

= 30m/s

30m/s = 0 m/s average speed

= 30/2

= 15m/s

t = 60 minutes/15(meters/second)

= 4 seconds (the second option)

2.  Height of building = (v^2 - u^2)/2g

= (0 - (39.2 * 39.2) / (2 * ( - 9.8))

= 78.4 m (option B)

3.Use vf^2 = vi^2 + 2as

0 = 384.16 - 19.6s

19.6s = 384.16

s  = 19.6 m (option C)

4.

Time taken to walk first 1 Km= 1/5 hr

Time taken to walk second 1 Km = 1/7 hr

Speed = Distance travelled/time

Speed =2/ (1/5 + 1/7)

= 2/(12/35)

= 2 x 35/12

= 35/6

= 5.8 Km/hr (the first option)

Hope this helps, and please mark me brainliest if it does!

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