You have two flashlights that operate on 1.50-V D batteries. The first flashlight uses two batteries in a chain, and the second uses five batteries in a chain. Each flashlight has a current of 2.50 A flowing through its circuit. What power is being transferred to the bulb in each flashlight

The first flashlight,

P = 7.5 W

The second flashlight,

P = 18.75 W

Explanation:

P = VI Equation 1

Where P = Power, V = Voltage, I = current.

For the first flashlight,

Given: I = 2.5 A, and V = 1.5×2 (The first uses two battery in chain) = 3 V

Substitute into equation 1

P = 3(2.5)

P = 7.5 W.

For the second flash light,

P = VI

Given: I = 2.5 A, V = 1.5×5 ( The second uses five batteries in a chain) = 7.5 V

Substitute into equation 1

P = 2.5(7.5)

P = 18.75 W.

i think it's 35 meters