8000 kg engine pulls a train of 5 wagons, each of 2000 kg, along a horizontal track. If the engine exerts a force of 40000 N and the track offers a friction force of 5000 N, then calculate the net accelerating force

The net force of engine on total mass of train is 35000 N

The net acceleration is 1.944 m/s²

Explanation:

Here we have;

Mass of each wagon of train = 2000 kg

Number of wagons = 5

Total mass of wagons = 5 × 2000 = 10000 kg

Mass of engine = 8000 kg

Total mass, m of train (engine plus wagons) = 10000 + 8000 = 18000 kg

Force exerted by train = 40000 N

Friction force due to the railway track = 5000 N

Net force, F of engine on total mass of train = 40000 - 5000 = 35000 N

Formula for force, F = Mass, m × Acceleration, a  

35, 000 = 18,000 × a

a = 35,000/18,000 = 35/18 m/s²

The net acceleration = 1.944 m/s².

the answer is f1 and d2 because if you put equal force on those two points the beam would balance trust me on this

this is an example of "committed" time.

committed time, as contracted time, takes need over essential and available time since it is seen as profitable work. it alludes to the time allotted to keep up a home and family. at the point when a man is commuting using committed time this individual may feel that the drive is an obligation to family, for example, strolling youngsters to class or driving a mate to work. contracted and committed time clients may feel that their commute could really compare to the commute of important or leisure time clients on the grounds that their commute is profitable work. in this manner, they might be more disposed to pick a mechanized method of movement.