A uniform horizontal rod of mass 2.1 kg and
length 0.25 m is free to pivot about one end
...
Physics, 30.05.2020 05:00 yasminothman02
A uniform horizontal rod of mass 2.1 kg and
length 0.25 m is free to pivot about one end
as shown. The moment of inertia of the rod
about an axis perpendicular to the rod and
through the center of mass is given by I =
m ℓ^2 /2. If a 9.6 N force at an angle of 78◦
to the horizontal acts on the rod as shown, what is the
magnitude of the resulting angular acceleration about the pivot point? The acceleration
of gravity is 9.8 m/s^2
Answer in units of rad/s^2
Picture for more info
Answers: 1
Physics, 22.06.2019 10:10, randlemccray4305
What is the angular momentum of the bar about the axle?
Answers: 3
Physics, 22.06.2019 12:30, tigistamare03
When a vertical beam of light passes through a transparent medium, the rate at which its intensity i decreases is proportional to i(t), where t represents the thickness of the medium (in feet). in clear seawater, the intensity 3 feet below the surface is 25% of the initial intensity i0 of the incident beam. what is the intensity of the beam "10" feet below the surface? (give your answer in terms of i0. round any constants or coefficients to five decimal places.)
Answers: 2
Physics, 23.06.2019 04:31, JFrocks2480
Water flows through a garden hose which is attached to a nozzle. the water flows through hose with a speed of 2.19 m/s and through the nozzle with a speed of 19.8 m/s. calculate the maximum height (in m) to which water could be squirted if it emerges from the nozzle and emerges with the nozzle removed.
Answers: 1
Mathematics, 01.07.2019 13:40
Mathematics, 01.07.2019 13:40
English, 01.07.2019 13:40
Mathematics, 01.07.2019 13:40
English, 01.07.2019 13:40
Physics, 01.07.2019 13:40