An electric kettle supplies 20,000J of energy to heat 0.5kg of water. What is the temperature change? The specific heat capacity of water is 4200J/kg°C.

The change in temperature is 9.52°C

Explanation:

Since, the heat supplied by the electric kettle is totally used to increase the temperature of the water.

Thus, from the law of conservation of energy can be stated as:

Heat Supplied by Electric Kettle = Heat Absorbed by Water

Heat Supplied by Electric Kettle = m C ΔT

where,

Heat Supplied by Electric Kettle = 20,000 J

Mass of water = m = 0.5 kg

Specific Heat Capacity of Water = C = 4200 J/kg.°C

Change in Temperature of Water = ΔT

Therefore,

20,000 J = (0.5 kg)(4200 J/kg.°C) ΔT

ΔT = 20,000 J/(2100 J/°C)

ΔT = 9.52°C

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .