A deuteron consists of one proton and one neutron. A deuteron moving horizontally enters a uniform, vertical magnetic field of 0.500 T. It then travels in a circular arc of radius 55.6 cm. How fast was the deuteron moving just before it entered the field? Let the mass of the deuteron m = 3.34 × 10^–27 kg and the charge on a proton q = 1.60 × 10^–19 C. (1 point)

Explanation:

Let the velocity of deuteron be v then force on it in magnetic field

Bqv , B is magnetic field and q is charge on deuteron . This force will provide centripetal force for circular path so

mv² / r = Bqv   m is mass of deuteron and r is radius of circular path

v = Bqr / m

(.5 x 1.6 x 10⁻¹⁹ x 55.6 x 10⁻² )/ 3.34 x 10⁻²⁷

= 13.31 x 10⁶ m /s

the total distance that martina travels that day is

(distance from home to mom's office) plus (distance from mom's office to school)

plus (distance from school to library) plus (distance from library to friend's house)

plus (distance from friend's house to martina's house).

(we don't know what any of these distance actually is.)