A 1.5 volt, AAA cell supplies 750 milliamperes of current through a flashlight bulb for 5.0 minutes, while a 1.5 volt, C cell supplies 750 milliamperes of current through the same flashlight bulb for 20 minutes. Compared to the total charge transferred by the AAA cell through the bulb, the total charge transferred by the C cell through the bulb is

A) half as great

B) twice as great

C) the same

D) four times as great

Why??

D) four times as great

Explanation:

The current through a circuit or device is given by the formula:

I = q/t

q = (I)(t)

where,

I = current

q = charge

t = time

FOR AAA CELL:

I = 750 mA = 0.75 A

t = 5 min = (5)(60) sec = 300 sec

q = q₁

Therefore,

q₁ = (0.75 A)(300 sec)

q₁ = 225 Coulomb

FOR C CELL:

I = 750 mA = 0.75 A

t = 20 min = (20)(60) sec = 1200 sec

q = q₂

Therefore,

q₂ = (0.75 A)(1200 sec)

q₂ = 900 Coulomb

Thus, from the values of charges for both cells, it is clear that, Compared to the total charge transferred by the AAA cell through the bulb, the total charge transferred by the C cell through the bulb is:

D) four times as great

absorption lines are where light has been absorbed by the atom thus you see a dip in the spectrum whereas.

emission spectra have spikes in the spectra due to atoms releasing photons at those wavelengths.

explanation:

im sorry i dont know