The magnitude and direction exerted by two tugboats towing a ship are 1620kilograms, N35degreesW, and 1250kilograms, S50degreesW, respectively. Find the magnitude, in kilograms, and the direction angle, in degrees, of the resultant force.

Magnitude (in kilogram) of the resultant force,

Direction = 164.37°

Explanation:

The two forces exerted by the two tugboats are non zero vectors, therefore they can be expressed as:

For the 1620 kg tugboat in the direction N35degreesW

The direction of the force from the positive x - axis,

The equation above then becomes:

For the 1250 kg tugboat in the direction S50degreesW

The direction of the force from the positive x - axis,

The equation above then becomes:

The resultant vector will be given by:

The magnitude of the resultant is given by:

The direction will be given by :

Direction = 180 - 15.63 = 164.37°

54 degrees incident angle = reflected angle

angle is from normal turned to line of ray