A proton enters a magnetic field at a speed of 7.8 × 10^4 m/s. The magnetic field is oriented at a 45° angle to the direction of the proton, and the strength of the field is a constant 3.0 T. What is the magnitude of the force acting on the proton? Let the charge of the proton equal 1.6 × 10^−19 C.
1.2 x 10^-14 N
2.0 x 10^-13 N
7.2 x 10^-14 N
2.6 x 10^-14 N
Answers: 3
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