This question checks that you can use the formula of the electric field due to a long, thin wire with charge on it. The field due to an infinitely long, thin wire with linear charge density LaTeX: \lambda λ is LaTeX: \vec{E} = \frac{1}{4\pi\epsilon_0}\frac{2\lam bda}{r}\hat{r}E → = 1 4 π ϵ 0 2 λ r r ^. Imagine a long, thin wire with a constant charge per unit length of -6.6LaTeX: \times10^{-7}× 10 − 7 C/m. What is the magnitude of the electric field at a point 10 cm from the wire (assuming that the point is much closer to the wire's nearest point than to either of its ends)? Give your answer in units of kN/C.

E = -118 KN / C

Explanation:

In this exercise we are given the expression of the electric field for a wire

       E = 1 /4πε₀ 2λ / r

they also indicate the linear density of charge

     λ = 6,6 10⁻⁷ C / m

ask to calculate the electric field at a position at r = 10 cm from the wire

    k = 1 /4πε₀  = 8,988 10⁹ N m² / C²

    E = 8,988 10⁹ 2 (-6.6 10⁻⁷ / 0.10)

     E = -1.18 105 N / C

we reduce to KN / C

    1 KN / C = 10³ N / C

   E = -1.18 10² KN / C

   E = -118 KN / C

the negative sign indicates that the field is directed to the charged

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm.   the wire diameter is d = 0.9 mm.   the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a                                          

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2)   in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation:

are there options? cause you ain’t. real specific