Calcular la longitud de un péndulo que oscila a 10 Hz en santa fe de bogota, sabiendo que en esta ciudad la aceleracion de la gravedad es de 978 cm/s2.

Explanation:

The period equation for a pendulum is given by:

and we know that T = 1/f, where f is the frequency, so we will have:

Now, we just need to solve this equation for L.

I hope it helps you!

the answer is a)

mark brainliest

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y