How many grams of nitrogen gas are needed to produce 34 g of ammonia

28 grams

Explanation:

The equation for the reaction is

3H(2) + N(2) -> 2NH(3)

Then we have.

The molar mass, M of ammonia is 17 g/mol.

34 grams of ammonia, NH3 then would be

34 g / 17 g/mol

= 2 moles

2 moles of ammonia will be obtained from

(2 * 1) / 2

= 1 mole of nitrogen

The molar masses of nitrogen is 28 g/mol

2 moles of nitrogen corresponds to 1 * 28 = 28 grams.

the maxium height is 34m/s