3.7.6. A satellite is in a circular orbit around the Earth. If it is at an altitude equal to twice the radius of the Earth, 2RE, how does its speed v relate to the Earth's radius RE, and the magnitude g of the acceleration due to gravity on the Earth's surface?a)b)c)d)e)

Explanation:

For acceleration due to gravity

g = GM / R²   ( 1 )

At height 2R , radius of orbit is 3R .

If speed of satellite be v

m v² / 3R = GMm / (3R)² ( centripetal force = gravitational force )

v² = GM / 3R ( 2 )

Dividing (1) and (2)

v² / g = R / 3

v² = gR / 3

v = √( gR / 3 )

0.3x0.21x0.08kg=mass 1 sheet

mass 500 = 500xmass 1

volume pile = 0.3x0.2x0.048

density=mass/volume= 500xmass 1/0.3x0.2x0.048

v patient student

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