A bowling ball has an initial momentum of +30 kg m/s and hits a stationary bowling pin. After the collision, the bowling ball leaves with a momentum of +13 kg • m/s. What is the magnitude of the final momentum of the bowling pin if it has a mass of 1.5 kg? 0 kg • m/s 11 kg • m/s 17 kg • m/s 43 kg • m/s

Momentum of the bowling pin is 17kgm/s

Explanation:

P(initial of ball)=+30 kg m/s

P(initial of pin)=0  because its velocity is 0

P initial = P final

30= P(ball) + P(pin)

30=13+P(pin)

P(final of pin)=+13 kg m/s and P(final of ball)= 30-13=17kgm/s

answer: 0.20

explanation: this can only be the answew because all the other measuremnets are not close

the small 0.38-kg slider is known to move from position a to position b along the vertical-plane slot. determine (a) the work done on the body by its weight and (b) the work done on the body by the spring. the distance r = 0.70 m, the spring modulus k = 154 n/m, and the unstretched length of the spring is 0.53 m

explanation:

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