"If a ball of mass M is dropped from a height h onto a spring with spring constant k (whose equilibrium positions is at height 0), compresses the spring an additional distance (L/2), and then rebounds, what height will the ball reach? Express your answer symbolically."

So I was thinking something along the lines of h= M*k*(L/2) but I'm not sure :/ Any guidiance?

Did the proton move into a region of higher potential or lower potential? did the proton move into a region of higher potential or lower potential? because the proton is a negative charge and it accelerates as it travels, it must be moving from a region of higher potential to a region of lower potential. because the proton is a negative charge and it accelerates as it travels, it must be moving from a region of lower potential to a region of higher potential. because the proton is a positive charge and it slows down as it travels, it must be moving from a region of higher potential to a region of lower potential. because the proton is a positive charge and it slows down as it travels, it must be moving from a region of lower potential to a region of higher potential. request answerpart bwhat was the potential difference that stopped the proton? express your answer with the appropriate units.î”v î” v = nothingnothingrequest answerpart cwhat was the initial kinetic energy of the proton, in electron volts? express your answer in electron volts. ki k i = nothing ev request answerprovide feedback

If vx = 7.00 units and vy = -7.60 units, determine the magnitude of v⃗ . determine the direction of v⃗ .

Which of the following are appropriate acceleration units?