A box with a total surface area of 1.88 m^2
and
a wall thickness of 2.44 cm is made of an insulating material. A 14.1 W electric heater
inside the box maintains the inside temperature at 18.6
◦C above the outside temperature.
Find the thermal conductivity of the insulating material.
Answer in units of W/m ·
◦ C.

9.8x10^(-3) w/m°C

Explanation:

Quantity of heat(Q)=14.1w

Distance(d)=2.44cm=2.44/100=0.0244m

Area(a)=1.88m^2

Temperature change(t)=18.6°C

thermal conductivity(k)=?

K=(Qxd) ➗ (a x t)

K=(14.1x0.0244) ➗ (1.88x18.6)

K=0.34404 ➗ 34.968

K=9.8x10^(-3) w/m°C

hotter stars = bluer stars

electromagnetic shielding is the practice of reducing the electromagnetic field in a space by blocking the field with barriers made of conductive or magnetic materials. shielding is typically applied to enclosures to isolate electrical devices from their surroundings, and to cables to isolate wires from the environment through which the cable runs. electromagnetic shielding that blocks radio frequency electromagnetic radiation is also known as rf shielding.

the shielding can reduce the coupling of radio waves, electromagnetic fields and electrostatic fields. a conductive enclosure used to block electrostatic fields is also known as a faraday cage. the amount of reduction depends very much upon the material used, its thickness, the size of the shielded volume and the frequency of the fields of interest and the size, shape and orientation of apertures in a shield to an incident electromagnetic

from wikipedia