A fly undergoes a displacement of -5.80 m while accelerating at -1.33m/s^2 for 4.22s. What is the initial velocity of the fly?

1.43 m/s

Explanation:

Given:

Δx = -5.80 m

a = -1.33 m/s²

t = 4.22 s

Find: v₀

Δx = v₀ t + ½ at²

-5.80 m = v₀ (4.22 s) + ½ (-1.33 m/s²) (4.22 s)²

v₀ = 1.43 m/s

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