Objects 1 and 2 attract each other with a electrostatic force of 36.0 units. If the charge of Object 2 is tripled, then the new electrostatic force will be units.

Explanation:

Force of attraction between two charges is 36N

Then from coulombs electrostatic law.

The force of attraction or repulsion between two charges (q1 and q2) is directly proportional to the product of the force and inversely proportional to the square of the distance apart.

F = kq1•q2 / r².

kq1•q2 / r² = 36

Now, we are told that the second charges has increased by a factor of 3

Then,

q2' = 3q2

So, since the first charge is contact, the radius is constant and k is constant,

Then,

F is directly proportional to the second charge, so if the second charge is triple then the force is tripled

Then,

F' = 3F = 3 × 36 = 108 units

Unit of force is newton

F' = 108N

Also,

F' = kq1•q2' / r²

F' = kq1•3q2 / r².

F' = 3 × kq1•q2 / r²

Since, kq1•q2 / r² = 36

Then,

F' = 3 × 36

F' = 108 units

F' = 108N

the answer is a 3.8cm

explanation:

a.   mass number from atomic number