Find the force between a 3 C charge and a 2 C charge separated by a distance of 3 meters.

Force,

Explanation:

Given that,

Charge 1,

Charge 2,

Distance between charges, d = 3 m

We need to find the force between charges. The electric force between charges is given by :

k is electrostatic constant

So, the force between charges is . Hence, this is the required solution.

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft

could you add the photo?

explanation: