A 0.65-T magnetic field is perpendicular to a circular loop of wire with 73 turns and a radius of 18 cm. If the magnetic field is reduced to zero in 0.12 s, what is the magnitude of the induced emf?

40.25 V

Explanation:

Parameters given:

Initial magnetic field, B1 = 0.65 T

Final magnetic field, B2 = 0 T

Number of turns, N = 73

Radius of loop, r = 18 cm = 0.18 m

Time taken, Δt = 0.12 s

The magnitude of the EMF induced in a loop of wire due to a changing magnetic field is given as:

V = | [-N * A * (B2 - B1)] / Δt |

Where A = area of loop

Area of loop = πr²

Therefore, the magnitude of the EMF induced will be:

V = | [-N * πr² * (B2 - B1)] / Δt |

V = | [-73 * π * 0.18² * (0 - 0.65)] / 0.12 |

V = |40.25| V

V = 40.25 V

This is the magnitude of the EMF induced in the loop of wire.

answer: the exterior temperature of commercial jet planes as they leave the stratosphere and return to the ground increases steadily.

explanation:

the lower most layer of atmosphere is troposphere which extends from 0 to 12 km above the surface of the earth. the temperature initially decreases as distance is increased from the earth's surface. commercial jets fly in lower part of the stratosphere. the stratosphere extends upto 50 km. the temperature in stratosphere starts rising again due to presence of ozone which traps the uv rays.

thus, when the planes leave the stratosphere and return to the ground, the exterior temperature increases steadily.

area of focus