A car is originally traveling at 15.0 m/s on a straight horizontal road. The driver applies the brakes, causing a car to decelerate uniformly at 4.00 m^2 until it comes to rest. Calculate the car's stopping distance.

28.13 m

Explanation:

Parameters given:

Initial speed of the car, u = 15 m/s

Acceleration of the car, a = -4 m/s ²

(The acceleration is negative because it is a deceleration)

We can find the distance traveled by the car by applying of the Newton's equations of motion:

v² = u² + 2 * a * s

Where v = final velocity of the car (0 m/s since the car comes to rest)

s = distance moved by the car

Therefore:

0² = 15² + (2 * -4 * s)

0 = 225 - 8s

=> s = 225/8

s = 28.13 m

The distance moved by the car before it comes to a stop is 28.13 m.

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