A single-turn square loop of side L is centered on the axis of a long solenoid. In addition, the plane of the square loop is perpendicular to the axis of the solenoid. The solenoid has 1250turns per meter and a diameter of 6.00 cm, and carries a current of 2.50 A. Find the magnetic flux through the loop when (a) LPart A: Find the magnetic flux through the loop when L= 2.75 cm .

Part B: Find the magnetic flux through the loop when L= 5.60 cm .

Part C: Find the magnetic flux through the loop when L= 13.5 cm .

a) 0.029Tcm^2

b) 0.122Tcm^2

c) 0.714Tcm^2

Explanation:

To find the magnetic flux in the loop it is necessary to calculate the magnetic field generated by the solenoid. This is calculated by using the following formula:

mu_o: magnetic permeability of vacuum = 4pi*10^{-7}T/A

N: turns of the solenoid = 1250

I: current in the solenoid = 2.50A

By replacing all these values you obtain

To know what is the flux in the loop, you take into account that the effective area of the loop, in which the magnetic field crosses it, is determined by the cross area of the solenoid. Hence, you compute the cross area of the solenoid:

This is the maximum value for the effective area of the loop:

a) for L=2.75cm ->  A = 7.56cm^2. The area of the loop is lower than the As. Hence, you use the area of the loop:

b) for L=5.60cm -> A = 31.36cm^2. The same as before:

c) for L=13.5cm -> A = 182.25cm^2. This value is higher than As. Hence you use As:

scattering of light by tiny particles in air to produce the colors we see on sky, is dependent on the following factors:

(i) wavelength of light

(ii) size of the scattering particle  

(iii) distance traveled by light through the atmosphere.

according to rayleigh's law of scattering, the amount of scattering is inversely proportional to the fourth power of its wavelength. shorter the wavelength, greater is its scattering. hence violet/blue light is scattered more than red.

sun's light is a composite light ( visible light) with wavelengths in the range 400 nm (violet) to 700 nm (red). as sunlight passes through our atmosphere, the molecules of air scatter light according to their wavelengths. during sunrise and sunset, the sun's position is below the horizon. hence light from the sun travels a greater distance in the atmosphere when compared to its position a noon.

as sunlight enters the earth's atmosphere, blue light is scattered away and at the end of its journey in the sky, only red and orange wavelengths remain in the beam.

hence at sunrise and sunset, the sky appears reddish orange.