The trunk of a elephant may extend up to 2.1 m. It acts much like an organ pipe only open at one end when the elephant blows air through it. Calculate the fundamental frequency of the sound the elephant can create with its trunkIf the elephant blows even harder, the next harmonic may be sounded. What is the frequency of the first overtone?

 f = 40.5 Hz,   f = 121.4 Hz

Explanation:

As they indicate that we approach the elephant's trunk as a system with one side closed and the other open. On the closed side there is a node and the open side has a maximum, so we have ¼ wavelength at this distance

             L = ¼ λ

For higher order resonance we have

           L = 1 (¼ λ )       fundamental

           L = 3 (¼ λ )      1st harmonic

           L = 5 (¼ λ )      3 harmonic

Wave speed is related to wavelength and frequency

        v = λ  f

         f = v /λ

Let's apply the initial equations to this problem

Fundamental frequency

        λ  = 4L

        f = v / 4L

The speed of sound is v = 340 m / s

         f = 340 / (4 2.1)

         f = 40.5 Hz

The first harmonic

            λ = 4/3 L

            f= v 3 / 4L

           f = 3 340 / (4 2.1)

           f = 121.4 Hz

explanation:

areas w steep slopes, west coast, rocky mountains, and appalachian mountains

i think it because equal matrices have equal dimensions, only square matrices can be symmetric. for all indices and . every square diagonal matrix is symmetric, since all off-diagonal elements are zero. in linear algebra, a real symmetric matrix represents a self-adjoint operator over a real inner product space.