Walter and John leave in their cars at the same time. Walter drives 252 miles. John drives 10 miles per hour faster than Walter and travels 312 miles. If Walter and John arrive at their destinations at the same time, determine how fast Walter is driving?

42 miles per hour

Explanation:

Let d = distance moved by Walter = 252 miles and D = distance moved by John = 312 miles. Let v be the speed of Walter and V be the speed of John. From the question, V = v + 10. Since they both arrive at the same time, and time = distance/speed

d/v = D/V

d/v = D/(v + 10)

v/d = (v + 10)/D

Substituting the values of  d and D , we have

v/252 = (v + 10)/312

v + 10 = 312v/252

v + 10 = 1.238v

collecting like terms, we have

1.238v - v = 10

0.238v = 10

v = 10/0.238 = 42 miles per hour

So Walter is driving at a speed of 42 miles per hour

the answer is kevlar

this is an example of "committed" time.

committed time, as contracted time, takes need over essential and available time since it is seen as profitable work. it alludes to the time allotted to keep up a home and family. at the point when a man is commuting using committed time this individual may feel that the drive is an obligation to family, for example, strolling youngsters to class or driving a mate to work. contracted and committed time clients may feel that their commute could really compare to the commute of important or leisure time clients on the grounds that their commute is profitable work. in this manner, they might be more disposed to pick a mechanized method of movement.