Calculate the braking distance for a vehicle traveling at 30 mi/h (13.4 m/s) with an acceleration of - 9.0 (m/s)/s while breaking.

Braking distance of vehicle is 9.97 m

Explanation:

It is given initial velocity of the vehicle u = 13.4 m/sec

Acceleration of the vehicle

As the vehicle finally stops so final velocity of the vehicle v = 0 m/sec

We have to find the braking distance s

From third equation of motion

s = 9.97 m

So braking distance of the vehicle is 9.97 m

answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg

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