Sheet metal of two different alloys is produced by rolling to 0.1 mm thickness. You must select one of these alloys for a sheet forming operation. To make the selection, tensile samples are cut from each alloy at 0o , 45o , and 90o to the rolling direction. The initial gauge section of each tensile sample is 0.75 mm width. After subjecting all samples to the same tensile load, th

Alloy A is best chosen for the sheet forming operation

Explanation:

taking both alloy A and B into consideration;

For alloy A;

the true strain ration, R₀ = width strain / thickness strain

   R₀ = in (0.65/0.75) / in (0.092/0.1) = 1.716

at 45⁰  and 90⁰, the true strain ratio becomes;

R45⁰ = in (0.63/0.75) / in (0.093/0.1) = 2.4025

R90⁰ = in (0.67/0.75) / in (0.087/0.1) = 0.8099

where R(avg) = (R₀+2Ras+Rao) / A = (1.716+2(2.4025)+0.8099) = 3.0340

R(avg) = 3.0340

For alloy B;

R₀ = in (0.7/0.75) / in (0.082/0.1) = 0.3477

R45⁰ = in (0.69/0.75) / in (0.083/0.1)  = 0.4475

R90⁰ = in (0.71/0.75) / in (0.078/0.1) = 0.2206

R(avg) = (R₀+2Ras+Rao) / A = (0.3477+2(0.4475)+0.2206) = 0.365825

R(avg) = 0.365825

comparing both we have that,

R(avg) for allow A > R(avg) for allow B

∴ Alloy A is the best to be selected for sheet formation operation.

cheers i hope this helps!!!1

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz

as technology advances, new experiments often expose problems in accepted theories. c

hope i

-lavira: )