In Parts B and C you saw that, according to Bohr's postulate, the electron radius r and the electron velocity v only have certain allowable values. Plug the values obtained for these two quantities into the energy statement given below (E=) to arrive at a new statement for the allowed energy levels in the Bohr atom. Express answer in terms of e, m, n, h, \epsilon _{0} . Equations:

v=nh/2mr\pi

r=n^{2}h^{2}\epsilon _{0}/m\pi e^{2}

E=\frac{1}{2}mv^{2}-(e^{2}/4\pi r\epsilon _{0})

Explanation:

Given:

We want to substitute the values of r and v into the Energy Statement.

First, we substitute r into v for simplicity.

Then,

The energy statement in terms of e,m, n,h and is:

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explanation:

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂