A spaceship carrying a light clock moves at a speed of 0.960c relative to an observer on Earth. If the clock on the ship advances by 1.00 s as measured by the space travelers aboard the ship, how long did that advance take as measured by the observer on Earth?

A) 0.96 s
B) 1.2 s
C) 2.6 s
D) 3.6 s
E) 5.8 s

(A) The time taken as measured by the observer on Earth is 0.96 s.

Explanation:

Given;

relative speed of spaceship to an observer on Earth, v = 0.960c

time of the spaceship as it advances, t = 1.00 s

time of advance observed on Earth, t = ?

Speed = distance / time

Distance = speed x time

Assuming constant distance in the spaceship advancement;

Therefore, the time taken as measured by the observer on Earth is 0.96 s.

The correct option is "A" 0.96 s

grav force prop 1/r squared 2r all squared is 4rsquared 1/4rsquared quartered

the answer would most likely be c, because if it's a comical piece of information, it may likely not be true, if it's a site that allows anybody to edit the content, it could mean a five year old is typing the info, and if it's a tv show produced by a celeb, it may have a biased opinion.