Cual es el modulo del vector diferencia (a - b) entre dos vectores que forman un angulo de 30° entre si y cuyos módulos son 2m y 8m. Grafica (Les agradecería muchísimo si me ayudan)

|a-b|=6.34m

Explanation:

To find the difference between the vector you can use the formulas for the magnitude of a vector and also for the doc product between two vectors:

a1, a2, a3: components of a vector

b1, b2, b3: components of b vector

a: magnitude of a = 2m

b: magnitude of b = 8m

angle = 30°

By squaring the first two equations

Then, you multiply by 2 the third equation:

Now, you sum the first two equations ans take the difference with the third equation. Thus, you obtain a perfect square trinomial:

This last expression is the square of the magnitude of the difference a-b. Hence you have:

thus, the magnitude of the difference is 6.34m

a=d/t

a="triangle"v/t

explanation:

a = acceleration