Physics, 04.12.2019 14:31 dchannakhone84

What's the difference between beam balance and spring balance?

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A spring balance will give a different mass reading on the Moon from that on Earth. A beam balance however, will give the same reading.Explain why.

Beam Balance:

Beam balance measures mass.

Mass is the amount of matter the object has.

The S.I. unit of mass is kg

Spring Balance:

Spring balance measures weight not mass.

Disadvantage: It requires gravity to measure.

The S.I. unit of weight is newton (N).

That is why when we are in outer space, we become lighter-there is less gravity!

Mass remains constant while weight is dependent on the gravitational pull of the planet. Mass only changes with a change in matter that results in a change of volume.

Mass remains constant throughout. Only weight changes with gravitational acceleration. Mass will only change with a change in the volume of matter in the body.

Answer from: Quest

Iagree c would be the answer

Answer from: Quest

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

$x(t)=ax(x-6)$

where $a$ is unknown. because the position is parabolic, there is symmetry about the midpoint at $t=3$ , and we know that

$x(3)=10\implies -9a=10\implies a=-\dfrac{10}9$

so that the position function is

$x(t)=-\dfrac{10}9x(x-6)$

which means the velocity is

$v(t)=\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac{20}9x+\dfrac{60}9$

then the total distance traveled is

$\displaystyle\int_{t=0}^{t=6}|v(t)|\,\mathrm dt=\left\{\int_{t-0}^{t=3}-\int_{t=3}^{t=6}\right\}v(t)\,\mathrm dt=20$

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at $x=0$ and ends at $x=0$ , so its displacement is 0.

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