If the Hubble Space Telescope is 598 m above the surface of the Earth and is traveling at 7.56 x 103 m/s, how long does it take the Hubble Space Telescope to orbit the earth? (Radius of the earth RE= 6.38 x 106 m, Mass of the earth ME = 5.98 x 1024 kg)

5069.04 seconds

Explanation:

The parameter we are looking for is called the Orbital period of the Hubble Space Telescope.

It is given as:

where r = radius of orbit of Hubble Space Telescope

G = gravitational constant =

M = Mass of earth

We are given that:

r = radius of the earth + distance of HST from earth

r =

M =

Therefore, T will be:

The orbital period of the Hubble Space Telescope is 5069.04 seconds.

neither accurate nor precise.

find the sum of the two horizontal vectors and the sum of the two vertical vectors

isoceles right angled triangle